Determina l'equazione della circonferenza passante per i punti A(4; 1) e B(2;2) e avente il centro sulla retta r di equazione {x} -{2y} = {0}
Solve the following equations by factorization method: 5[x/(x+1)]^2 4[x/(x+1)] 1=0; x not equal to 1
![Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}} Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}}](https://www.skuola.net/news_foto/2017/10/dominio-1647.jpg)
Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}}
![How do you solve the following system using substitution?: 1/x + 1/y = 3/4, 3/x - 1/y = 1/4 | Socratic How do you solve the following system using substitution?: 1/x + 1/y = 3/4, 3/x - 1/y = 1/4 | Socratic](https://useruploads.socratic.org/HaPTlYA0T0WGkM2N5EuM_mat2.jpg.jpeg)